求x^2+xy+y^2-3x-3y+1=0的实数解
来源:百度知道 编辑:UC知道 时间:2024/05/28 22:32:27
x^2+xy+y^2-3x-3y+1=0
x^2+(y-3)x+(y^2-3y+1)=0
判别式(y-3)^2-4(y^2-3y+1)>=0
-3y^2+6y+5>=0
y^2-2y-5/3<=0
(y-1)^2-8/3<=0
y有无数个解,题目有问题
0.183503588174361 0.183503588174361
-8.28428E-07
1.81000993416375 1.82296600808252
-2.14071E-07
有无数组
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